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Question: Calculate the lattice energy of a salt \[MX(s)\]​ from the date given below: Heat of formation of ...

Calculate the lattice energy of a salt MX(s)MX(s)​ from the date given below:
Heat of formation of MX(ΔH)  =550  kJ/molMX\left( {\Delta H} \right)\; = - 550\;kJ/mol
Heat of sublimation of M(S)=80  kJ/molM\left( S \right) = 80\;kJ/mol
Heat of dissociation of X2(D)=155  kJ/mol{X_2}\left( D \right) = 155\;kJ/mol
Ionization energy of M(IE)=347  kJ/molM\left( {IE} \right) = 347\;kJ/mol
Electron affinity of X(EA)=343  kJ/molX\left( {EA} \right) = - 343\;kJ/mol
A. 835KJ/mol - 835KJ/mol
B. 938.5 kJ/mol - 938.5{\text{ }}kJ/mol
C. 711.5 kJ/mol - 711.5{\text{ }}kJ/mol
D. 638.5 kJ/mol - 638.5{\text{ }}kJ/mol

Explanation

Solution

Born Haber cycle is mainly used to calculate the lattice energy. It also involves steps such as sublimation energy (ΔHsub  ),\left( {\Delta {H_{sub}}\;} \right), dissociation energy (D),\left( D \right), ionisation energy(I),\left( I \right), electron affinity(E)\left( E \right) and heat of formation of crystal (H).\left( H \right). Represented in the form of
Δ H  f  0  = ΔH  sub  + D2+ IE + EA  +U\Delta {\text{ }}H{\;_{f{\;^0}}}\; = {\text{ }}\Delta H\;sub\; + {\text{ }}\dfrac{D}{2} + {\text{ }}IE{\text{ }} + {\text{ }}EA\; + U

Complete step by step answer:
Born Haber cycle is a cycle of enthalpy change of process and The energy terms involved in building a crystal lattice( MX)\left( {{\text{ }}MX} \right) such as -
Step  1\;1 - convert solid ( M)\left( {{\text{ }}M} \right) to gaseous ( M)\left( {{\text{ }}M} \right)is called enthalpy of sublimation (ΔH  sub).\left( {\Delta H\;sub} \right).
Step 22 - convert gaseous(X)\left( X \right) molecule to atoms is called enthalpy of dissociation(D).\left( D \right).
Step 33 - Conversion of gaseous ( M)\left( {{\text{ }}M} \right) atom into (M ion)\left( {M{\text{ }}ion} \right) in gaseous state is called ionisation energy .
Step 44 - Conversion of gaseous (X)\left( X \right) atom into gaseous X   ionX{\text{ }}\;ion is known as electron gain enthalpy and represented by EA  .{E_A}\;.
Step 55 - The amount of energy released when one mole of solid crystalline compound is obtained from gaseous ions is called lattice energy(U)\left( U \right)
M(s)+ 12X  (g)MX(s)M\left( s \right) + {\text{ }}\dfrac{1}{2}X\;\left( g \right) \to MX\left( s \right)
The Born-Haber Cycle can be reduced to a single equation:
Heat of formation= Heat of atomization + Dissociation energy+ (sum of Ionization energies) + (sum of Electron affinities)+ Lattice energy

The enthalpies are represented in figure.
These steps are represented as -
Δ H  f0  = ΔH  sub  + D/2 + IE + EA  +U\Delta {\text{ }}H{\;_f}^0\; = {\text{ }}\Delta H{\;_{sub}}\; + {\text{ }}D/2{\text{ }} + {\text{ }}IE{\text{ }} + {\text{ }}{E_A}\; + U
Now, Putting values as -
ΔHf  =      S + 0.5D + IE + EA + U\Delta {H_f}\; = \;\;\;S{\text{ }} + {\text{ }}0.5D{\text{ }} + {\text{ }}IE{\text{ }} + {\text{ }}EA{\text{ }} + {\text{ }}U
550 =    80+1552+347343+U- 550{\text{ }} = \;\;80 + \dfrac{{155}}{2} + 347 - 343 + U
    U=711.5kJ/mol\;\;U = - 711.5kJ/mol
lattice energy of salt =  711.5  kJ/mol. = \; - 711.5\;kJ/mol.
Option (c ) is correct.
Note: Born Haber process is a method that allows us to observe and analyze energies in a reaction. It mainly helps in describing the formation of ionic compounds from different elements. Born Haber cycle is a process that leads to the formation of a solid crystalline ionic compound from the elemental atoms in their standard state and of the enthalpy of formation of the solid compound such that the net enthalpy becomes zero.