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Question: Calculate the inductance of unit length of a double tape line as shown in the figure. The tapes are ...

Calculate the inductance of unit length of a double tape line as shown in the figure. The tapes are separated by a distance h which is considerably less than their width b.

A) μ0hb\dfrac{{{\mu _0}h}}{b}
B) μ0h2b\dfrac{{{\mu _0}h}}{{2b}}
C) 2μ0hb\dfrac{{2{\mu _0}h}}{b}
D) 2μ0hb\dfrac{{\sqrt 2 {\mu _0}h}}{b}

Explanation

Solution

To find the required inductance per unit length of a double tape line we have to figure out the magnetic field within the interior region of the double tape with the help of ampere-circuital law after that we will calculate the magnetic flux link with the magnetic field within its interior region. Finally, we use the formula in order to calculate the magnetic inductance as: L=ϕIL = \dfrac{\phi }{I}, where LL is the inductance ϕ\phi is the magnetic flux and II is the current.

Complete step-by-step answer:
To calculate the required inductance per unit length of the double tape we apply ampere-circuital law first.

Let us consider the amperian- loop PQRS as shown above. The line PQ is parallel to the length b and also parallel to the magnetic field B\vec B within the interior region in between the tape while the line QR and PS are perpendicular to B\vec B.
Applying ampere-circuital law:
Bb+0+Bb+0=μ0IBb + 0 + Bb + 0 = {\mu _0}I (Along line QR and SP B\vec B and dld\vec l are perpendiculars so there dot product are also zero)
2Bb=μ0I\Rightarrow 2Bb = {\mu _0}I
B=μ0I2b\Rightarrow B = \dfrac{{{\mu _0}I}}{{2b}}
Similarly, the magnetic field due to lower surface B=μ0I2bB = \dfrac{{{\mu _0}I}}{{2b}}
Now, total magnetic field BT=2×μ0I2b{B_T} = 2 \times \dfrac{{{\mu _0}I}}{{2b}}
BT=μ0Ib\Rightarrow {B_T} = \dfrac{{{\mu _0}I}}{b}
Magnetic flux link with BT{B_T}will be written as-
ϕ=BT×Area\phi = {B_T} \times Area
As
So,
ϕ=μ0Ilhb\Rightarrow \phi = \dfrac{{{\mu _0}Ilh}}{b}
Calculating inductance as
L=ϕIL = \dfrac{\phi }{I}……………(i)
Substitute the value of ϕ=μ0Ilhb\phi = \dfrac{{{\mu _0}Ilh}}{b} in the equation (i) we get
L=μ0lhbL = \dfrac{{{\mu _0}lh}}{b}
Now, we calculate the required inductance per unit length.
Ll=μ0hb\dfrac{L}{l} = \dfrac{{{\mu _0}h}}{b}.
Thus the inductance per unit length of a double tape line(Ll)=μ0hb\left( {\dfrac{L}{l}} \right) = \dfrac{{{\mu _0}h}}{b}
Hence, Option (A) is the correct answer.

Note: In order to answer such kinds of conceptual questions students must have conceptual clarity of the Ampere-circuital law. Along with that, one should have the ability to relate a link between the concept behind the laws and its implementation while solving the conceptual problems. One should also remember the various fact-based short formulas and their implementation while solving tricky numerical problems.