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Question: Calculate the exact number of grams of aluminum that should react with \( 35 \) mL of \( 2.0 \) M hy...

Calculate the exact number of grams of aluminum that should react with 3535 mL of 2.02.0 M hydrochloric acid? Balance the given equation;
\\_HCl + \\_Al \to \\_AlCl_3 + \\_H_2

Explanation

Solution

When we get an equation, we must always check if it is balanced. If it is not balanced, balance it. We use stoichiometry to do this. The procedure we must follow in order to reach the final answer is; first since molarity of hydrochloric acid is given, we must find the number of moles in it, then we can proceed to calculate the grams of aluminum that will satisfy the equation.

Complete answer:
Always start a question like this by writing down what all are given and what we need to find;
Molarity of hydrochloric acid ( HClHCl ) =2.0M= 2.0M
Volume of hydrochloric acid in liters ( HClHCl ) =35mL=0.035L= 35mL = 0.035L
To find: Number of grams of aluminum =?= ?
Since our given equation is not balanced, by stoichiometry we can balance the equation. If the equation is balanced it is easier to calculate the quantities and we can only proceed to calculations after balancing any given unbalanced equation.
Balanced equation: 2Al+6HCl3H2+2AlCl32Al + 6HCl \to 3H_2 + 2AlCl_3
Let us see what our next step is; it is to find for HClHCl the number of moles that are involved in reaction.
We use molarity for this:
Molarity=number  of  moles  of  HClvolume  of  HClMolarity = \dfrac{{number\;of\;moles\;of\;HCl}}{{volume\;of\;HCl}}
2.0M=number  of  moles0.035L\Rightarrow 2.0M = \dfrac{{number\;of\;moles}}{{0.035L}}
number  of  moles=0.070\Rightarrow number\;of\;moles = 0.070 moles
\therefore 0.0700.070 moles of HClHCl are needed in the reaction.
With the help of our balanced equation we can now determine number of grams of aluminum needed;
number  of  grams=(ratio  of  moles)×(molecular  mass  of  Al)×(number  of  moles  of  HCl)number\;of\;grams = (ratio\;of\;moles) \times (molecular\;mass\;of\;Al) \times (number\;of\;moles\;of\;HCl)
number  of  grams=(2mol6mol)(26.98g1mol)(0.070moles)number\;of\;grams = (\dfrac{{2mol}}{{6mol}})(\dfrac{{26.98g}}{{1mol}})(0.070\,moles)
Number  of  grams=0.63g\therefore Number\;of\;grams = 0.63g of Aluminum is required to satisfy the equation.

Note:
Aluminum is a metal so it mostly reacts with non-metals, and since it exists at room temperature, in order for reactions to take place, external agents like heat must be used. Even though it is a metal it is proved that aluminum cannot rust, which is why it is very reliable. But usage of aluminum is not encouraged as it is difficult to degrade, that is it is non-biodegradable.