Solveeit Logo

Question

Chemistry Question on Stoichiometry and Stoichiometric Calculations

Calculate the concentration of NaOHNaOH solution in g/ml. which has the same normality as that of a solution of HClHCl of concentration 0.04g/ml0.04 \,g/ml

A

0.0215g/ml0.0215\, g/ml

B

0.032g/ml0.032 \,g/ml

C

0.48g/ml0.48\, g/ml

D

0.0438g/ml0.0438 \,g/ml

Answer

0.0438g/ml0.0438 \,g/ml

Explanation

Solution

N=n×MN=n \times M M=no.of.molesVol.in(L)=0.0436103M=\frac{no.of. moles}{Vol. in \left(L\right)}=\frac{\frac{0.04}{36}}{10^{-3}} =1.1×103103=1.1=\frac{1.1\times10^{-3}}{10^{-3}}=1.1 N=1×1.1=1.1NN=1\times1.1=1.1\,N M of NaoH =x40103=\frac{\frac{x}{40}}{10^{-3}} where x is wt. o f NaOH in g. 1.1×103=x401.1\times10^{-3}=\frac{x}{40} x=4.4×102x=4.4\times10^{-2} =0.044g/ml=0.044 \,g/ ml