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Question: Calculate the amount of lime obtained by heating \(400\,kg\) of limestone. A. \(56\,kg\) B. \(11...

Calculate the amount of lime obtained by heating 400kg400\,kg of limestone.
A. 56kg56\,kg
B. 112kg112\,kg
C. 224kg224\,kg
D. 280kg280\,kg

Explanation

Solution

As we all know that when limestone commonly known as calcium carbonate is heated in a limited amount of air or even in absence of air, it results in the formation of calcium oxide also called quicklime and carbon dioxide.

Complete answer:
As we all know that when limestone commonly known as calcium carbonate (CaCO3)(CaC{O_3}) is heated in limited amount of air or even in absence of air, it decomposes into calcium oxide (CaO)(CaO) also called quicklime and carbon dioxide CO2C{O_2}. Calcium oxide is yellow when it is hot but becomes white when it cools down. We can write the chemical equation for this decomposition as:
CaCO3(s)CaO(s)+CO2(s)CaC{O_3}(s) \rightleftharpoons CaO(s) + C{O_2}(s)
We know the molecular mass of limestone is 100gmol1100\,gmo{l^{ - 1}}, molecular mass of quick lime is 56gmol156\,gmo{l^{ - 1}}and molecular mass of carbon dioxide is 44gmol144\,gmo{l^{ - 1}}.
From the above equation and stoichiometric calculations which are based on the stoichiometric coefficient of reactants as well as products, we can say that 1 mole of limestone produces with 1 mole of quick lime and 1 mole of carbon dioxide or in other words we can say that 100g100\,g or 100kg100\,kg of limestone reacts with 56g56g or 56kg56\,kg of quick lime and 44g44\,g or 44kg44\,kg of carbon dioxide respectively.
CaCO3CaO+CO2CaCO_3 \rightleftharpoons CaO+CO_2
1mole            1mole        1mole1\, mole\;\;\;\;\;\;1\, mole\;\;\;\;1\, mole
100g                  56g                44g100\,g\;\;\;\;\;\;\;\;\;56\,g\;\;\;\;\;\;\;\;44\,g
Now, we can also say that 100kg100\,kg of limestone reacts with 56kg56\,kg of quick lime and 44kg44\,kg of carbon dioxide, so 400kg400\,kg of limestone will produces:
=56×400100= \dfrac{{56 \times 400}}{{100}}
=224kg= 224\,kg of quicklime.
And if we asked to calculate the amount of carbon dioxide, so 400kg400\,kg of limestone will produce carbon dioxide as:
=44×400100 =176kgofCO2 = \dfrac{{44 \times 400}}{{100}} \\\ = 176\,kg \,of \,CO_2

**Therefore, our correct answer is C. 224kg224\,kg

Note:**
Using stoichiometric calculation we can identify the limiting reagents also. Limiting reagent are those chemicals which are present in lesser quantity and will be consumed first in the process of conversion of reactants into products. These chemicals can decide the amount of product formed as well as amount of reactant consumed.