Question
Question: Calculate the amount of heat required to convert \( 45\,g \) of water at \( {43^o}\,C \) to stream a...
Calculate the amount of heat required to convert 45g of water at 43oC to stream at 100oC ?
Solution
First the given water must be heated to 100oC . Then the 100o water must be turned into steam. Using the equation Q=mcΔT we can calculate the amount of energy for heating the water to 100oC . Where Q is energy input, m is mass of the matter to heat, c is specific heat capacity of the matter to heat and ΔT is the temperature change of the matter.
Complete Step By Step Answer:
Heat is the form of energy that is transferred between systems or objects with different temperatures. Heat is generally measured in joules ( J ).
The amount of energy calculated by using formula
Q=mcΔT -----(1)
Given mass of water m=45g , initial temperature Ti=43oC , and final temperature Tf=100oC .
Then ΔT=Tf−Ti=57oC
Also, we know that c=4187JKg−1K1 (the specific heat capacity of water)
Then the equation (1) becomes
Q=(0.045)×(4187)×(57)
⇒Q=10721≈10.7kJ
Now we must turn the water into steam. This is done by increasing the potential energy of the water without changing its temperature using something called Specific latent heat of evaporation of water. It is given by the equation
Q=mL ------(2)
Where, L is the specific latent heat
We know that the latent heat of evaporation of water
L=2264.705kJ/kg
Plugging it in to the equation:
Q=2264.705×0.045≈101.9kJ
So, the total energy change =101.9+10.7≈112.6kJ
Hence the amount of heat required to convert 45g of water at 43oC to stream at 100oC is 112.6kJ .
Note:
Heat has no shape, no mass, no colour, no odour, no volume. Also note that heat flowing from the high-temperature system to the low-temperature system. Heat energy is also known as thermal energy.
Specific latent heat of evaporation of water is the energy amount required to convert a unit mass of water into steam at constant temperature.