Question

Calculate $K_c$ for the reversible process given below if $K_p = 167$ and $T = 800^?C$. ${CaCO_{3(s)} <=> CaO_{(s)} + CO_{2(g)}}$

• A. $1.95$
• B. $1.85$
• C. $1.89$
• D. $1.60$

Answer 1

Answer: (C)

$1.89$

Answer 2

$K_{p}=K_{c}\left(RT\right)^{\Delta n}$ $\Delta n=n_{p}-n_{R}=1$ $167=K_{c}\left(0.0821\times1073\right)$ $K_{c}=\frac{167}{0.0821\times1073}=1.89$