Question

Calculate $K_{C}$ for the reversible process given below if $K_{P}=167$ and $T=800^{\circ} C$ $CaCO _{3}( s ) \rightleftharpoons CaO ( s )+ CO _{2}( g )$

• A. 1.95
• B. 1.85
• C. 1.89
• D. 1.6

Answer 1

Answer: (C)

1.89

Answer 2

$K_{P}=K_{C}(R T)^{\Delta n}$
for $e q^{n} CaCO _{3}( s ) \rightleftharpoons CaO ( s )+ CO _{2}( g ), \Delta n =1$
$K_{C}=\frac{K_{p}}{(R T)^{\Delta n}}$
$=-\frac{167}{(0.0821 \times 1073)^{1}}$
$=1.89$