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Question: Calculate how much oxygen (in grams) required to combust 10 moles of magnesium from the given equati...

Calculate how much oxygen (in grams) required to combust 10 moles of magnesium from the given equation: 2Mg+O22MgO2Mg + {O_2} \to 2MgO

Explanation

Solution

Look at the stoichiometry of the reaction. Here, 2 moles of Mg requires 1 mole of O2{O_2}. Hence, 1 mole of Mg requires 0.5 moles of O2{O_2}. Now, calculate the number of moles of O2{O_2} required for the combustion of 10 moles of Mg. 1 mole of O2{O_2} weighs 32g. The molar mass of Mg is 24g/mol.

Complete step by step answer:
In the given reaction, magnesium undergoes oxidation by oxygen to form Magnesium dioxide. It is a combustion reaction.
2Mg+O22MgO2Mg + {O_2} \to 2MgO
A combustion reaction is a reaction in which a substance reacts with oxygen gas, releasing energy in the form of light and heat.
Before understanding how to calculate the amount of O2{O_2} required for the reaction, let us analyze the information available from the balanced chemical equation.
Here, the reactants are magnesium and oxygen. The product formed is magnesium oxide.
The coefficients 2 for Mg and MgO are the stoichiometric coefficients. They represent the number of moles (or molecules) taking part in the reaction or formed in the reaction.
According to the given chemical reaction,
One mole of O2{O_2} reacts with 2 moles of Mg to give 2 moles of MgO.
Therefore, 1 mole of Mg requires 0.5 moles of O2{O_2}.
Now, we need to calculate the number of moles of O2{O_2} required to react with 10 moles of Mg.
The number of moles of O2{O_2} required to react with 10 moles of Mg = 10 ×\times 0.5 = 5 moles.
We are asked to find the amount of oxygen in grams.
We know that 1 mole of oxygen gas weighs 32 g. Therefore, 5 moles weigh 5 ×\times 32 = 160g.

The answer is: 160g of O2{O_2} is required for the combustion of 10 moles of Mg.

Note: Ensure that the given reaction is balanced. According to the law of conservation of mass, a balanced chemical equation has the same number of atoms of each element on both sides of the equation.
-1 mole of O2{O_2} is equal to 22.4L. This applies to all gases.
-Remember to use the molecular mass (in grams) of oxygen and not the atomic weight. The atomic weight of oxygen is 16g/mol while the molecular mass of oxygen is 32g/mol.