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Question: Calculate following in \[5.6g\] of \[nitrogen\] A. Number of moles B. Number of molecules of \[{...

Calculate following in 5.6g5.6g of nitrogennitrogen
A. Number of moles
B. Number of molecules of N2{N_2}
C. Number of atoms of nitrogennitrogen

Explanation

Solution

To find the above all solutions, one must be familiar with the concept of moles. The above quantity is the provided or given mass of the elementnitrogennitrogen. Simply putting that value in the number of moles formula, we will be able to find the solution.

Complete answer:
One mole is the amount of a substance that contains as many particles or entities as there are atoms in exactly 12g12g of the 12C^{12}C isotopes. It is similar to the quantities as we denote one dozen or a gross for 1212 or 144144 items. The S.I. unit is molemole and the symbol for mole is molmol. The mole of a substance always contains the same number of entities, no matter what the substance may be. This is represented by which is equal to 6.022×1023atoms/mol6.022 \times {10^{23}}atoms/mol
Also the molar mass is the mass of one mole of a substance in gramsgrams. The molar mass in gramsgrams is numerically equal to atomic or molecular formula mass in uu
The number of moles is given by the formula-
No. of moles=Given massMolar massNo.{\text{ }}of{\text{ }}moles = \dfrac{{Given{\text{ mass}}}}{{Molar{\text{ mass}}}}
Now that we are familiar with these concepts we will solve the given question.
A. To find the number of moles of nitrogennitrogen atom we will use the same formula-
No. of moles=Given massMolar massNo.{\text{ }}of{\text{ }}moles = \dfrac{{Given{\text{ mass}}}}{{Molar{\text{ mass}}}}
Molar mass of N2{N_2}= 2×14=28g/mol2 \times 14 = 28g/mol
No. of moles= 5.628=0.2mol\dfrac{{5.6}}{{28}} = 0.2mol
B. Number of molecules of N2{N_2}
=6.022×1023×no. of moles of N2= 6.022 \times {10^{23}} \times no.{\text{ of moles of }}{N_2}
=6.022×1023×0.2= 6.022 \times {10^{23}} \times 0.2
=1.2×1023= 1.2 \times {10^{23}}
C. Number of atoms of N2{N_2}
(There are two nitrogennitrogen atoms in N2{N_2})
=2×no. of N2 molecules= 2 \times {\text{no}}{\text{. of }}{{\text{N}}_2}{\text{ molecules}}
=2×1.2×1023=2.4×1023= 2 \times 1.2 \times {10^{23}} = 2.4 \times {10^{23}}

Note:
Atoms and molecules are extremely small in size and their numbers in even a small amount of any substance is really very large. To handle such large numbers, a unit of similar magnitude is required. Therefore the mole concept was introduced.