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Question: Calcium carbonate reacts with aqueous \(HCl\) to gives \(CaC{l_2}\) and \(C{O_2}\) according to the ...

Calcium carbonate reacts with aqueous HClHCl to gives CaCl2CaC{l_2} and CO2C{O_2} according to the reaction CaCO3(s)+2HCl(aq)CaCl2(aq)+CO2(g)+H2O(l)CaC{O_3}\left( s \right) + 2HCl\left( {aq} \right) \to CaC{l_2}\left( {aq} \right) + C{O_2}\left( g \right) + {H_2}O\left( l \right) . The mass of CaCO3CaC{O_3} which is required to react completely with 25ml25ml of 0.75M0.75M HClHCl is:
(A)\left( A \right) 1.825g1.825g
(B)\left( B \right) 0.9375g0.9375g
(C)\left( C \right) 1.8357g1.8357g
(D)\left( D \right) 0.46875g0.46875g

Explanation

Solution

First we have to know the molar mass of a chemical compound is defined as the mass of a sample of that compound divided by the amount of substance in that sample, measured in moles. The molar mass is a bulk, not molecular, property of a substance. The molar mass of a compound is calculated by adding there standard atomic masses in (gmol)\left( {\dfrac{g}{{mol}}} \right) of each atom.

Complete step by step answer:
Since, we have to calculate the mass of calcium carbonate (CaCO3)\left( {CaC{O_3}} \right) , Let us calculate the mass of calcium carbonate (CaCO3)\left( {CaC{O_3}} \right) is xx grams.
Molar mass xx of CaCO3CaC{O_3} is the sum of the masses of calcium ++carbon ++ 33 oxygen == 40+12+4840 + 12 + 48 =100g = 100g .
In the calcium carbonate(CaCO3)\left( {CaC{O_3}} \right), the molar mass is 100g100g
1000ml1000ml Of 0.75HCl0.75HCl =0.75 = 0.75 mole
So, 25ml25ml of hydrochloric acid (HCl)\left( {HCl} \right) will contain HClHCl$ = 0.75 \times \dfrac{{25}}{{1000}} = 0.01875 2molofhydrochloricacidmol of hydrochloric acid\left( {HCl} \right)reactswithreacts with 1molofmol ofCaC{O_3}So, So,0.01875molofhydrochloricacidmol of hydrochloric acid\left( {HCl} \right)willreactwithwill react with\dfrac{1}{2} \times 0.01875 = 0.009375Molarmassofcalciumcarbonate Molar mass of calcium carbonate\left( {CaC{O_3}} \right) = 100gHence,themassof Hence, the mass of0.009375molofcalciumcarbonatemol of calcium carbonateCaC{O_3} = no.ofmolesno.of moles \times molarmassMassofcalciumcarbonatemolar mass Mass of calcium carbonate\left( {CaC{O_3}} \right) = 0.009375 \times 100g.g . = 0.9375g.Hence,thecorrectoptionis. **Hence, the correct option is\left( C \right)$ .**

Additional information: The molar mass is the mass of a given chemical element or chemical compound (g)\left( g \right) divided by the amount of substance (mol)\left( {mol} \right) .

Note:
We must know the definition of atomic mass unit is the atomic mass of an element is the average mass of the atoms of an element measured in atomic mass unit (amu, also as Daltons, D). Where 1amu=1.6605×1024g1\,\,amu = 1.6605 \times {10^{ - 24}}g .