Question

Calcium carbonate decomposes on heating to give calcium oxide and carbon dioxide. How much volume of $CO_2$ will be obtained by thermal decomposition of $50\, g$ of $CaCO_3$?

• A. $1\,L$
• B. $11.2\,L$
• C. $44\,L$
• D. $22.4\,L$

Answer 1

Answer: (B)

$11.2\,L$

Answer 2

\underset{\text{100,g}}{ {CaCO3}} ${->}$ $CaO +$ \underset{\text{1,$mole = 22.4$,L}}{ {CO2}} $100\, g$ of $CaCO_3$ at $STP$ gives $22.4\, L$ of $CO_ 2$ $50 \,g$ of $CaCO_{3}$ will produce $\frac{22.4}{100}\times50$ $= 11.2\, L$ of $CO_{2}$