Question

Calcium carbide reacts with water to produce:
$(a){\text{ ethane }} \\\ (b){\text{ ether }} \\\ (c){\text{ acetylene }} \\\ (d){\text{ alcohol}} \\\$

Answer 1

Hint – In this question use the chemical reaction that when $Ca{C_2}$reacts with water that is $Ca{C_2}\left( s \right) + 2{H_2}O\left( l \right) \to {C_2}{H_2}\left( g \right) + Ca{\left( {OH} \right)_2}\left( g \right)$. The products on the right hand side are the results of the reactants.

Complete answer:
As we know calcium carbide is a solid element and the chemical formula of calcium carbide =$Ca{C_2}$.
Now as we know water is liquid whose chemical formula =${H_2}O$.
Now the chemical reaction of these two compounds is shown below,
$\Rightarrow Ca{C_2}\left( s \right) + 2{H_2}O\left( l \right) \to {C_2}{H_2}\left( g \right) + Ca{\left( {OH} \right)_2}\left( g \right)$
Here we use one unit of calcium carbide and two units of water so the resultant product is acetylene (${C_2}{H_2}$) which is a gas.
So when calcium carbide reacts with water it produces acetylene.
So this is the required answer.

Hence option (C) is the correct answer.

Note – ${C_2}{H_2}$ thus formed over this reaction is also termed as ethyne formally known as acetylene. It is a hydrocarbon and the simplest alkyne. Acetylene is commonly used for welding and cutting. The welding that uses acetylene is also known as oxy-cutting or gas cutting. Acetylene is basically a colorless gas.