Question

“$Ca{\left( {OH} \right)_2}$is called baryta water and $Ba{\left( {OH} \right)_2}$is called lime water.” Answer whether the above statement is true or false. If true enter 1, else enter 0.

Answer 1

The elements of Group 2 include beryllium (Be), magnesium (Mg), calcium (Ca), strontium (St), barium (Ba) and radium (Ra.) These elements are commonly known as the alkaline earth metals with an exception of beryllium. These are so called because their hydroxides and oxides are alkaline in nature and they are found in the earth’s crust.

Complete step by step answer:
Calcium and Barium both belong to the 2nd group in the periodic table. The hydroxides of elements of the 2nd group of the periodic table are obtained by the reaction of their oxides with water and are all white crystalline solids. The alkali metal hydroxides are the strongest of all bases and dissolve freely in water with evolution of enormous amounts of heat due to intense hydration.
Our question includes the hydroxides of Calcium and Barium so in order to give the answer, first we have to get their basic idea.
Calcium hydroxide, traditionally called slaked lime is an inorganic compound with the chemical formula $Ca{\left( {OH} \right)_2}$. It is a colorless crystal or white powder and is produced when calcium oxide (quicklime) is mixed with water. Calcium hydroxide has many applications, including food preparation, where it can be identified as E number E526. Calcium hydroxide adopts a polymeric structure. It has many names including hydrated lime, caustic lime, builders' lime etc. Limewater is the common name for a saturated solution of $Ca{\left( {OH} \right)_2}$ (calcium hydroxide).
Barium hydroxide has the chemical formula $Ba{\left( {OH} \right)_2}{\left( {H2O} \right)_x}$. The monohydrate (when x =1), known as baryta or baryta water, is one of the principal compounds of barium (Ba). This is a white granular monohydrate used for commercial purposes. Barium hydroxide can be prepared by dissolving Barium Oxide in water:
$BaO{\text{ }} + {\text{ }}9{\text{ }}{H_2}O{\text{ }} \to {\text{ }}Ba{\left( {OH} \right)_2}\cdot8{H_2}O$
From the above discussion, it is clear that the given statement is wrong.

Therefore, the answer is 0.

Note: Remember that if the amount of water (${H_2}O$) attached to the molecule is different then its name also gets changed accordingly. Let’s take sulphate of calcium for example.
-$CaS{O_4}{\text{ }}\cdot{\text{ }}2{\text{ }}{H_2}O$ is a dihydrate and commonly known as gypsum.
- $CaS{O_{4{\text{ }}}}\cdot{\text{ }}0.5{\text{ }}{H_2}O$is a hemihydrate and commonly known as plaster of Paris.