Question

C6H12O6 $\underrightarrow{Zymase}$ A$\frac{\underrightarrow{NaOI}}{Δ}$B+CHI3
The number of carbon atoms present in the product B is_________.

Answer 1

The correct answer is: 1

$C_ 6 H _{12} O_ 6 \underrightarrow{Zymase}\,C_2H_2OH\underrightarrow{NaOl}\,\,HCOONA_{(B)}+CHl_3$