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Question

Chemistry Question on Thermodynamics

CvC_v values for monoatomic and diatomic gases respectively are

A

12R,32R\frac{1}{2}R, \frac{3}{2}R

B

32R,52R\frac{3}{2}R, \frac{5}{2}R

C

52R,72R\frac{5}{2}R, \frac{7}{2}R

D

32R,32R\frac{3}{2}R, \frac{3}{2}R

Answer

32R,52R\frac{3}{2}R, \frac{5}{2}R

Explanation

Solution

For monoatomic gas, Cv=32RC_{v}=\frac{3}{2}R For diatomic gas, Cv=52RC_{v}=\frac{5}{2}R