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Question: C (s) + O2 (g) \(\longrightarrow\)CO2, (g); \(\Delta\)H = –94.3 kcal/mol CO (g) +\(\frac{1}{2}\)O2(...

C (s) + O2 (g) \longrightarrowCO2, (g); Δ\DeltaH = –94.3 kcal/mol

CO (g) +12\frac{1}{2}O2(g) \longrightarrowCO2 (g); Δ\DeltaH = – 67.4 kcal/mo!

O2(g) \longrightarrow2O (g); Δ\DeltaH = 117.4 kcal/mol

CO (g) \longrightarrowC (g) + O(g) ;  Δ\DeltaH = 230.6 kcal/mol

Calculate Δ\DeltaH for C (s) \longrightarrowC (g) in kcal/mol.

C (s) \longrightarrowC (g) kcal/molΔ\DeltaH

A

171

B

154

C

117

D

145

Answer

145

Explanation

Solution

C(s) \longrightarrowC(g)

can be obtained as, Δ\DeltaH = Δ\DeltaH1 – Δ\DeltaH2 – 12Δ\frac{1}{2}\DeltaH3 + Δ\DeltaH4