Question
Question: C (s) + O2 (g) \(\longrightarrow\)CO2, (g); \(\Delta\)H = –94.3 kcal/mol CO (g) +\(\frac{1}{2}\)O2(...
C (s) + O2 (g) ⟶CO2, (g); ΔH = –94.3 kcal/mol
CO (g) +21O2(g) ⟶CO2 (g); ΔH = – 67.4 kcal/mo!
O2(g) ⟶2O (g); ΔH = 117.4 kcal/mol
CO (g) ⟶C (g) + O(g) ; ΔH = 230.6 kcal/mol
Calculate ΔH for C (s) ⟶C (g) in kcal/mol.
C (s) ⟶C (g) kcal/molΔH
A
171
B
154
C
117
D
145
Answer
145
Explanation
Solution
C(s) ⟶C(g)
can be obtained as, ΔH = ΔH1 – ΔH2 – 21ΔH3 + ΔH4