Question

$C{{H}_{3}}CON{{H}_{2}}\xrightarrow{Na+ROH}Z+{{H}_{2}}O$ what is $Z.$
(A) $C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}$
(B) $C{{H}_{3}}C{{H}_{2}}NC$
(C) $C{{H}_{3}}C{{H}_{2}}C{{H}_{3}}$
(D) $N{{H}_{2}}KON{{H}_{2}}$

Answer 1

Hint : We know that acetamide is an organic compound which releases nitrogen gas from the solution when reacted with $Na+ROH.$ It is the simplest amide derived from acetic acid. It finds some use as a plasticizer and as an industrial solvent.

Complete Step By Step Answer:
As we know, the amines are regarded as derivatives of ammonia in which one, two or all three hydrogen atoms are replaced by alkyl or aryl groups. They constitute an important class of organic compounds. The amines are classified as primary, secondary, or tertiary according to one, two or three hydrogen atoms of ammonia molecule are replaced by alkyl or aryl groups in ammonia molecule If one hydrogen atom of alkyl or aryl groups in ammonia molecule. If one hydrogen atom of ammonia is replaced by an alkyl or aryl group, a primary amine. Amines are regarded as derivatives of ammonia in which one, two or all three hydrogen atoms are replaced by alkyl or aryl groups. If two hydrogen atoms of ammonia are replaced by an alkyl or aryl group, we get secondary amine. If three hydrogen atoms of ammonia are replaced by an alkyl or aryl group, we get tertiary amine.
$\underset{Acetamide}{\mathop{C{{H}_{3}}CON{{H}_{2}}}}\,+4H\xrightarrow{Na+ROH}\underset{\text{ }Ethyl\text{ }Amine}{\mathop{C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}}}\,+{{H}_{2}}O$
Therefore, the correct answer is option A.

Note :
Remember that we can use “Hinsberg test” to distinguish between primary, secondary and tertiary amines. In this reaction, primary and secondary amines react with benzene sulphonyl chloride to form sulphonamides. The sulfonamide of primary amine is soluble in alkali while secondary amine is insoluble. Tertiary amines do not give this reaction.