Solveeit Logo
Login

Question

Question: \(C{H_3}CHO\) and \(C{H_3}COC{H_3}\) can not be extinguished by: A.Fehling solution B.Grignard r...

CH3CHOC{H_3}CHO and CH3COCH3C{H_3}COC{H_3} can not be extinguished by:
A.Fehling solution
B.Grignard reagent
C.Schiff’s reagent
D.Tollen’s reagent

Explanation

Solution

We know aldehydes and ketones are organic compounds that contain carbonyl groups. We can write the general formula of aldehydes as R−CHOR - CHO, here R is the alkyl group. We can write the general formula of ketones as R−CO−R′R - CO - R', here R and R’ is the alkyl group.

Complete step by step answer:

Aldehydes and ketones contain the carbonyl group.

In aldehydes, the carbonyl group is attached at the end of the hydrocarbon chain. The carbonyl carbon is bonded to at least one hydrogen.
Aldehydes have a general formula of R−CHOR - CHO. The general structure of an aldehyde is,

In ketones, the carbonyl group is attached to two carbon atoms. The general formula of a ketone is R−CO−R′R - CO - R'. The general structure of ketone is,

CH3CHOC{H_3}CHO is an aldehyde and CH3COCH3C{H_3}COC{H_3} is a ketone.
Fehling solution is used to differentiate aldehydes and ketones. The presence of brick red precipitate shows the presence of aldehyde (Fehling's test).
Therefore, Option (A) is incorrect.
Tollen’s reagent is used to differentiate aldehydes and ketones. Appearance of a silver mirror along the sides of the test tube indicates the presence of aldehyde (Tollen’s test).
Therefore, option (D) is incorrect.
Aldehyde/Ketone can be treated with 2-3 drops of Schiff’s base. The presence of pink color indicates the presence of aldehyde.
Therefore, option (C) is incorrect.
So, Schiff’s base, Tollen’s reagent and Fehling solution could differentiate CH3CHOC{H_3}CHO and CH3COCH3C{H_3}COC{H_3}.
Both aldehydes and ketones react with Grignard reagent.
Grignard reagent with aldehydes gives secondary alcohol.

Grignard reagent with ketones gives tertiary alcohol.

CH3CHOC{H_3}CHO and CH3COCH3C{H_3}COC{H_3} cannot be extinguished with Grignard reagent.
Therefore, the option B is correct.

Note:
We also know that aldehydes and ketones cannot form hydrogen bonds to one another, but they can form intermolecular hydrogen bonds with water. As result, the smaller members (five or fewer carbon atoms) are soluble in water. Aldehydes and ketones have lower boiling points when compared to carboxylic acid, representing the presence of weak intermolecular dipole-dipole forces. They do not form hydrogen bonds with other aldehydes or ketones because there is no oxygen-hydrogen bond in the carbonyl group. Due to weaker intermolecular hydrogen bonding in aldehydes and weaker dipole-dipole attractions, they have lower boiling points compared to carboxylic acids.