Question

$C{{H}_{3}}C{{H}_{2}}Cl$ undergoes homolytic fission, produces

• A. $CH _{3} \overset{\bullet}{C}H _{2}$ and $\overset{\bullet}{C}l$
• B. $CH _{3} \overset{\oplus}{C}H _{2}$ and $Cl ^{\ominus }$
• C. $CH _{3} \overset{\oplus}{C}H _{2}$ and \overset{\bullet{C}l
• D. $CH _{3} \overset{\oplus}{C}H _{2}$ and $Cl ^{\ominus}$

Answer 1

Answer: (A)

$CH _{3} \overset{\bullet}{C}H _{2}$ and $\overset{\bullet}{C}l$

Answer 2

In homolysis, the covalent bond is broken in such a way that each resulting species known as free radical. $CH _{3} CH _{2}- {->[{\text { Homolytic }}][{\text { fission }}]} CH _{3} \overset{\bullet}{ C } H _{2}+ { }^{\bullet}Cl$