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Chemistry Question on Alcohols, Phenols and Ethers

C6H5−CH=CHCHO−>[X]C6H5CH=CHCH2OH C_6H_5 - CH = CHCHO {->[X]} C_6H_5CH = CHCH_2OH In the above sequence XX can be:

A

H2/Ni{{H}_{2}}/Ni

B

NaBH4NaB{{H}_{4}}

C

K2Cr2O7/H+{{K}_{2}}C{{r}_{2}}{{O}_{7}}/{{H}^{+}}

D

both [a] and [b]

Answer

NaBH4NaB{{H}_{4}}

Explanation

Solution

NaBH4NaB{{H}_{4}} and LiAlH4LiAl{{H}_{4}} attacks only carbonyl group and reduce it into alcohol group. They do not attack on double bond. C6H5−CH=CHCHOCinnamic aldehyde−>[NaBH4]\underset{\text{Cinnamic aldehyde}}{C_6H_5 - CH = CHCHO} {->[NaBH_4]} C6H5−CH=CH.CH2OHCinnamic alcohol\underset{\text{Cinnamic alcohol}}{C_6H_5 - CH = CH . CH_2OH}