Question

$C_{6} H_{5}-C H=C H C H O \xrightarrow{X} C_{6} H_{5} C H=C H C H_{2} O H$ In the above sequence $X$ can be:

• A. $H_{2}/Ni$
• B. $NaBH_{4}$
• C. $K_{2}Cr_{2}O_{7}+H^{+}$
• D. both (a) and (b)

Answer 1

Answer: (B)

$NaBH_{4}$

Answer 2

$NaBH _{4}$ and $LiAlH _{4}$ attacks only carbonyl group and reduce it into alcohol group. They do not attack on double bond. $C _{6} H _{5}- \underset{\text{Cinnamic aldehyde}}{CH = CHCHO} \xrightarrow{ NaBH _{4}} C _{6} H _{5}- CH=\underset{\text{Cinnamic acid}}{CH . CH _{2} OH}$