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Chemistry Question on Aldehydes, Ketones and Carboxylic Acids

C4H10O−>[K2Cr2O7][H2SO4]C4H5O−>[I2/NaOH][Warm]CHI3C_4H_10 O { ->[{K_2Cr_2O_7}][{H_2SO_4}] }C_4H_5O { ->[{I_2/NaOH}][{\text{Warm}}] }CHI_3 Here, N is

A

B

C

D

Answer

Explanation

Solution

Given sequence of chemical equation is

C4H10O(N)−>[K2Cr2O7][H2SO4(stepI)]C4H8O−>[I2/NaOH][warm(stepII)]CHI3\underset{(N)}{C_4H_{10} O} { ->[{K_2Cr_2O_7}][{H_2SO_4 (step I)}] }C_4H_8O { ->[{I_2/NaOH }][{warm (step II)}] }CHI_3

Here, NN will be

(IUPAC name == Butan-2-ol)

It involves the oxidation of secondary alcohol to corresponding alcohol in the presence of K2Cr2O7K _{2} Cr _{2} O _{7} and H2SO4H _{2} SO _{4}
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It involves the iodoform reaction. Ketone formed in step I have one methyl group linked to the carbonyl carbon atom are oxidised by sodium hypohalite to sodium salts of corresponding carboxylic acids having one carbon atom less than that of carbonyl compound.