Question

${{C}_{2}}{{H}_{5}}OH+SOC{{l}_{2}}\xrightarrow{Pyridine}X+Y+Z,$ in this reaction X, Y and Z respectively, are

• A. ${{C}_{2}}{{H}_{4}}C{{l}_{2}},S{{O}_{2}},HCl$
• B. ${{C}_{2}}{{H}_{5}}Cl,S{{O}_{2}},HCl$
• C. ${{C}_{2}}{{H}_{5}}Cl,SOCl,HCl$
• D. ${{C}_{2}}{{H}_{4}},S{{O}_{2}},C{{l}_{2}}$

Answer 1

Answer: (B)

${{C}_{2}}{{H}_{5}}Cl,S{{O}_{2}},HCl$

Answer 2

${{C}_{2}}{{H}_{5}}OH+SOC{{l}_{2}}\xrightarrow{\text{Pyridine}}\underset{(X)}{\mathop{{{C}_{2}}{{H}_{5}}Cl}}\,+\underset{(Y)}{\mathop{S{{O}_{2}}}}\,+\underset{(Z)}{\mathop{HCl}}\,$ This method is known as Darzens method of reparation of alkyl chloride.