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Chemistry Question on Atomic Structure

C11H18O12C_{11}H_{18}O_{12}The value of the Rydberg constant (RHR_H) is 2.18×10−18 J2.18 \times 10^{-18} \, \text{J}. The velocity of an electron having mass 9.1×10−31 kg9.1 \times 10^{-31} \, \text{kg} in Bohr's first orbit of the hydrogen atom is:⋯×105 ms−1\dots \times 10^5 \, \text{ms}^{-1} (nearest integer).

Answer

Using the formula for the velocity of an electron:

v=2.18×106×Znv = 2.18 \times 10^6 \times \frac{Z}{n}

For hydrogen (Z=1,n=1Z = 1, n = 1):

v=2.18×106×11=2.18×106 ms−1≈22×105 ms−1v = 2.18 \times 10^6 \times \frac{1}{1} = 2.18 \times 10^6 \, \text{ms}^{-1} \approx 22 \times 10^5 \, \text{ms}^{-1}