Solveeit Logo

Question

Question: \[{{C}_{1}}\]and \[{{C}_{2}}\] are two circles with center \[{{O}_{1}}\] and \[{{O}_{2}}\] and inter...

C1{{C}_{1}}and C2{{C}_{2}} are two circles with center O1{{O}_{1}} and O2{{O}_{2}} and intersect each other at points AAand BB. If O1O2{{O}_{1}}{{O}_{2}} intersectABAB atMM then show that ΔO1AO2ΔO1BO2\Delta {{O}_{1}}A{{O}_{2}}\cong \Delta {{O}_{1}}B{{O}_{2}}

Explanation

Solution

Hint: We will try to show the two triangles ΔO1AB\Delta {{O}_{1}}AB and ΔO2AB\Delta {{O}_{2}}AB congruent using ‘SSS’ type of triangle congruence.

Given that two circles C1{{C}_{1}}and C2{{C}_{2}} with center O1{{O}_{1}}and O2{{O}_{2}} intersect each other at points AAand BB.
Also, O1O2{{O}_{1}}{{O}_{2}} intersects ABAB at MM.
Then, we have to show that ΔO1AO2ΔO1BO2\Delta {{O}_{1}}A{{O}_{2}}\cong \Delta {{O}_{1}}B{{O}_{2}}

Let us assume that the radius of the circle C1{{C}_{1}}be rr and the radius of the circle C2{{C}_{2}} be ss.
Proof:
In ΔO1AO2\Delta {{O}_{1}}A{{O}_{2}} and ΔO1BO2\Delta {{O}_{1}}B{{O}_{2}}, we have
O1A=O1B.....(i){{O}_{1}}A={{O}_{1}}B.....\left( i \right)
Both are radii of the same circle C1{{C}_{1}}.
O2A=O2B.....(ii)\Rightarrow {{O}_{2}}A={{O}_{2}}B.....\left( ii \right)
Both are radii of the same circle C2{{C}_{2}}.
Also, O1O2=O2O1....(iii){{O}_{1}}{{O}_{2}}={{O}_{2}}{{O}_{1}}....\left( iii \right)
Common sides of ΔO1AO2\Delta {{O}_{1}}A{{O}_{2}} and ΔO1BO2\Delta {{O}_{1}}B{{O}_{2}}
So, from equation (i),(ii)\left( i \right),\left( ii \right)and(iii)\left( iii \right), we get both triangles ΔO1AO2\Delta {{O}_{1}}A{{O}_{2}}and ΔO1BO2\Delta {{O}_{1}}B{{O}_{2}} are congruent with each other by ‘SSS’ type if triangle congruence.
Or,ΔO1AO2ΔO1BO2\Delta {{O}_{1}}A{{O}_{2}}\cong \Delta {{O}_{1}}B{{O}_{2}} by SSS type of triangle congruence.
(Here, ‘SSS’ type means side – side – side type of triangle congruence)
SSS – Theorem

Side - side - side postulate (SSS) states that two triangles are congruent if three sides of one triangle are congruent to the corresponding sides of the other triangle.
Here, from ΔABC\Delta ABC and ΔDEF\Delta DEF, we can say that
AB=DF....(a)AB=DF....\left( a \right)
AC=DE....(b)AC=DE....\left( b \right)
BC=EF....(c)BC=EF....\left( c \right)
So, from equation (a),(b)\left( a \right),\left( b \right) and (c)\left( c \right), we have ΔABCΔDEF\Delta ABC\cong \Delta DEF by SSS – type triangle congruence.

Note: Visualize the geometry first before attempting the question. Make a clear diagram of the required question which reduces the probability of error in your solution. Using the SSS theorem, we prove the congruence of the required triangles to prove what is given.