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Question: By which velocity a ball be projected vertically downward so that the distance covered by it in 5th ...

By which velocity a ball be projected vertically downward so that the distance covered by it in 5th second is twice the distance it covers in its 6th second (g=10m/s2g = 10m/s^{2})

A

58.8m/s58.8m/s

B

49m/s49m/s

C

65m/s65m/s

D

19.6m/s19.6m/s

Answer

65m/s65m/s

Explanation

Solution

By formula hn=u+12g(2n1)h_{n} = u + \frac{1}{2}g(2n - 1)

u102[2×51]=2{u102[2×61]}\mathbf{u}\mathbf{-}\frac{\mathbf{10}}{\mathbf{2}}\mathbf{\lbrack 2}\mathbf{\times}\mathbf{5}\mathbf{-}\mathbf{1\rbrack = 2\{ u}\mathbf{-}\frac{\mathbf{10}}{\mathbf{2}}\mathbf{\lbrack 2}\mathbf{\times}\mathbf{6}\mathbf{-}\mathbf{1\rbrack\}}

u45=2×(u55)u - 45 = 2 \times (u - 55)u=65m/s.u = 65m/s.