Question
Mathematics Question on integral
By using the properties of definite integrals, evaluate the integral: ∫02πcos5xdx
Answer
Let I=∫02πcos5xdx...(1)
cos5(2π−x)=cos5x
It is known that,
∫02aƒ(x)dx=2∫0aƒ(x)dx,ifƒ(2a−x)=ƒ(x)
=0ifƒ(2a−x)=−ƒ(x)
∴I=2∫0πcos5xdx
⇒I=2(0)=0[cos5(π−x)=−cos5x]