Question

By passing electric current, $NaClO_3$ is converted into $NaClO_4$ according to the following equation $Na ClO_3 + H_2 O \rightarrow NaClO_4 + H_2$ How many moles of $NaClO_4$ will be formed when three Faradays of charge is passed through $NaClO_3$ ?

• A. $0.75$
• B. $1.0$
• C. $1.5$
• D. $3.0$

Answer 1

Answer: (C)

$1.5$

Answer 2

The correct answer is C:$1.5$
$\underset{(+5)}{NaClO _{3}}+ H _{2} O \to \underset{(+7)}{NaClO _{4}}+ H _{2}$
2F charges required for give 2 moles of electrons therefore $3F$ of charge give $=\frac{3}{2}=1.5$ moles of electrons.
Hence, $1.5$ moles of $NaClO _{4}$ will be formed.