Question
Question: \(bx^{2} + cx + a = 0\)...
bx2+cx+a=0
A
{ – 1, 2}
B
{1, 2}
C
{ – 1, – 2}
D
{1, – 2}
Answer
{1, – 2}
Explanation
Solution
x2+xe−e=0x=6+6+6+....to∞, or 2<x<3
x=3 or x2+5∣x∣+4=0 log4{log2(x+8−x)}=0
{x∈R:∣x−2∣=x2}=does not gives any real root]