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Question

Question: \(bx^{2} + cx + a = 0\)...

bx2+cx+a=0bx^{2} + cx + a = 0

A

{ – 1, 2}

B

{1, 2}

C

{ – 1, – 2}

D

{1, – 2}

Answer

{1, – 2}

Explanation

Solution

x2+xee=0x=6+6+6+....to,x^{2} + xe - e = 0x = \sqrt{6 + \sqrt{6 + \sqrt{6 + ....\text{to}\infty}},} or 2<x<32 < x < 3

x=3x = 3 or x2+5x+4=0x^{2} + 5|x| + 4 = 0 log4{log2(x+8x)}=0\log_{4}\{\log_{2}(\sqrt{x + 8} - \sqrt{x})\} = 0

{xR:x2=x2}=\{ x \in R:|x - 2| = x^{2}\} =does not gives any real root]