Question

Bulb B₁(100W–250V) and bulb B₂(100 W – 200V) are connected across 250 V. What is potential drop across B₂?

• A. 200 V
• B. 250 V
• C. 98 V
• D. 48 V

Answer 1

Answer: (C)

98 V

Answer 2

Resistance of bulb B₁ , R₁ = $\frac{(250)^{2}}{100}$= 625 W

Resistance of bulb B₂, R₂ = $\frac{(200)^{2}}{100}$= 400 W

$V_{R_{2}}$= $\frac{R_{2}}{R_{1} + R_{2}}$× 250 = $\frac{400}{625 + 400}$× 250 = 98V