Question

Bromine is liberated, when aqueous solution of KBr is treated with:

• A. ${{I}_{2}}$
• B. $C{{l}_{2}}$
• C. $S{{O}_{2}}$
• D. $\text{dil}\text{.}\,{{H}_{2}}S{{O}_{4}}$

Answer 1

Answer: (B)

$C{{l}_{2}}$

Answer 2

Among the halogens, the element, placed above in the group, can displace the halogen (placed below in group) from its solution, hence, chlorine can displace bromine from ${{H}_{2}}{{O}_{2}}$ . $2KBr+C{{l}_{2}}\xrightarrow{{}}2KCl+B{{r}_{2}}$