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Question: Bromine atoms are available in two isotopes, \(_{35}^{79}Br\) (49.7 % ) and \(_{35}^{81}Br\) (50.3 %...

Bromine atoms are available in two isotopes, 3579Br_{35}^{79}Br (49.7 % ) and 3581Br_{35}^{81}Br (50.3 % ). The average atomic mass of bromine atom is:
(A) 79.016
(B) 80.076
(C) 80.006
(D) 81.016

Explanation

Solution

The atomic mass is the mass of an atom and the average atomic mass of an element is the sum of the masses of its isotopes each multiplied by its natural abundance.

Complete step by step answer:
Here use a formula of average atomic mass, i.e.
Average atomic mass of Br = Atomic  mass  of  Br3579  ×  Its  natural  abundance+Atomic  mass  of  Br3581  ×  Its  natural  abundance100\dfrac{Atomic\; mass \;of\; Br_{35}^{79}\; \times\;Its\;natural \;abundance + Atomic\; mass\; of\; Br_{35}^{81} \;\times \;Its\;natural\; abundance}{100}
Here is,
Percentage of Br3579Br_{35}^{79} = 49.7 %
Atomic mass of Br3579Br_{35}^{79} = 79
Percentage of Br3581Br_{35}^{81} = 50.3
Atomic mass of Br3581Br_{35}^{81} = 81
Apply a formula for putting a value.
Average atomic mass of Br = Atomic  mass  of  Br3579  ×  Its  natural  abundance+Atomic  mass  of  Br3581  ×  Its  natural  abundance100\dfrac{Atomic\; mass \;of\; Br_{35}^{79}\; \times\;Its\;natural \;abundance + Atomic\; mass\; of\; Br_{35}^{81} \;\times \;Its\;natural\; abundance}{100}
Average atomic mass of Br = [79×49.7+81×50.3100]\left[ {\dfrac{{79 \times 49.7 + 81 \times 50.3}}{{100}}} \right]
Average atomic mass of Br = [8000.6100]\left[ {\dfrac{{8000.6}}{{100}}} \right]
Average atomic mass of Br = 80.006

Therefore, from the above explanation the correct option is (C) 80.006.

Note: Bromine occurs in nature mainly in the form of two isotopes. Both are used in nuclear medicine. Br-81 is used for the production of radioisotopes. Vapours of bromine are very toxic.