Question

Both the roots of the given equation

$\left\lbrack - \frac{1}{13},\frac{1}{3} \right\rbrack$ are always.

• A. Positive
• B. Negative
• C. Real
• D. Imaginary

Answer 1

Answer: (C)

Real

Answer 2

Given equation

$kx^{2} + 1 =$

can be re-written as $kx + 3x - 11x^{2}$

$- 11, - 3$

$5,7$

$5, - 7$

Hence both roots are always real.