Question

Boron is unable to form $BF _{6}^{3}$ because of

• A. high electronegativity of boron
• B. high electronegativity of fluorine
• C. lack of d-orbitals in boron
• D. less difference in electronegativity between B and F

Answer 1

Answer: (C)

lack of d-orbitals in boron

Answer 2

Due to lack of d-orbitals in $B$, it is unable to form $BF _{6}^{3-}$ complex ion.