Solveeit Logo
Login

Question

Chemistry Question on Structure of atom

Boron has two stable isotopes, 10B(19)^{10}B (19)% and 11B(81)^{11}B (81)%. Average atomic weight for boron in the periodic table is

A

10.8

B

10.2

C

11.2

D

10

Answer

10.8

Explanation

Solution

Average atomic mass =R.A.(1)×M.No+R.A.(2)×M.No.R.A.(1)+R.A.(2)= \frac{R.A.\left(1\right) \times M.No + R.A.\left(2\right) \times M.No.}{R.A.\left(1\right) + R.A.\left(2\right) } where R.A. = relative abundance M.No = Mass number =19×10+81×11100=10.81= \frac{19 \times10 + 81 \times11}{100} = 10.81