Question
Question: Boiling point of water at 750mmHg is 96.63\(^{\circ }C\) . How much sucrose is added to 500g of wate...
Boiling point of water at 750mmHg is 96.63∘C . How much sucrose is added to 500g of water such that it boils at 100∘C . Molal elevation constant (Kb ) of H2O is 0.52K.kg.mol−1
Solution
elevation in boiling point of the solvent occurs when a non-volatile solute is added to the solvent. This question can be solved by using the relationship between elevation in boiling point and molality which is ΔTb=Kb×Msolutewsolute×wsolvent1000.
Complete step by step solution:
The boiling point of solvent increases in a solution when a solute is added to the solvent and this change in boiling point is directly proportional to the molal concentration (molality) of the solution formed. Mathematically it can be represented as
ΔTb=Kb×molality
ΔTb=Kb×Msolutewsolute×wsolvent1000 …(i)
Where, ΔTb= elevation in boiling point =100−96.63=3.37∘C=3.37K (given in the question)
Kb= Molal elevation constant=0.52K.kg.mol−1
wsolute= given mass of solute (sucrose in this case)
Msolute= molar mass of solute(sucrose)
Msolute= molar mass of sucrose (C12H22O11 )=12×12+22×1+11×16=342g/mol
wsolvent= given mass of water=500g
On rearranging equation (i), we get,
wsolute=ΔTb×Kbwsolvent×1000Msolute