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Question

Physics Question on Kinematics

Bob P is released from the position of rest at the moment shown. If it collides elastically with an identical bob Q hanging freely then velocity of Q, just after collision is (g = 10 m/s2)

A

1 m/s

B

4 m/s

C

2 m/s

D

8 m/s

Answer

2 m/s

Explanation

Solution

Velocity of P just before collision is = 2gl\sqrt{2gl}
= 2 m/sec
As collision is elastic and the mass of P and Q is equal therefore just after collision velocity of P is 0 and that of Q is 2 m/sec.

So, The correct answer is (C) : 2 m/sec.