Question

Block $B$ lying on a table weighs $W$. The coefficient of static friction between the block and the table is $\mu$. Assume that the cord between $B$ and the knot is horizontal. The maximum weight of the block $A$ for which the system will be stationary is

• A. $\frac{W \tan\theta}{\mu}$
• B. $\mu W \tan\,\theta$
• C. $\mu W\sqrt{1+ \tan^{2}\,\theta }$
• D. $\mu W\, \sin\,\theta$

Answer 1

Answer: (B)

$\mu W \tan\,\theta$

Answer 2

Let weight of $A$ is $W'$. From the free body diagram, For equilibrium of the system,