Solveeit Logo

Question

Question: Bird S is flying at \[5{\rm{ }}{{\rm{m}} {\left/ {\vphantom {{\rm{m}} {\rm{s}}}} \right. } {\r...

Bird S is flying at 5m/mss5{\rm{ }}{{\rm{m}} {\left/ {\vphantom {{\rm{m}} {\rm{s}}}} \right. } {\rm{s}}} towards south, and bird T is flying at 52m/mss5\sqrt 2 {\rm{ }}{{\rm{m}} {\left/ {\vphantom {{\rm{m}} {\rm{s}}}} \right. } {\rm{s}}} towards the south-east. Then, velocity of bird S relative to bird T is:
A. 102m/mss10\sqrt 2 {\rm{ }}{{\rm{m}} {\left/ {\vphantom {{\rm{m}} {\rm{s}}}} \right. } {\rm{s}}} South-West
B. 5m/mss5{\rm{ }}{{\rm{m}} {\left/ {\vphantom {{\rm{m}} {\rm{s}}}} \right. } {\rm{s}}} West
C. 102m/mss10\sqrt 2 {\rm{ }}{{\rm{m}} {\left/ {\vphantom {{\rm{m}} {\rm{s}}}} \right. } {\rm{s}}} North-West
D. 5m/mss5{\rm{ }}{{\rm{m}} {\left/ {\vphantom {{\rm{m}} {\rm{s}}}} \right. } {\rm{s}}} East

Explanation

Solution

The relative velocity of bird S relative to bird T is equal to the difference of their absolute velocities. We will draw the directions of bird S and bird T graphically, and we will find that the bird S is moving at an angle of 4545^\circ with east and south.

Complete step by step answer:
Let us first draw all the possible directions.

Here S represents the south, W represents the west, E represents east, and N represents north direction.
It is given that bird S is flying with 5m/mss5{\rm{ }}{{\rm{m}} {\left/ {\vphantom {{\rm{m}} {\rm{s}}}} \right. } {\rm{s}}} towards the south, and bird T is flying with 52m/mss5\sqrt 2 {\rm{ }}{{\rm{m}} {\left/ {\vphantom {{\rm{m}} {\rm{s}}}} \right. } {\rm{s}}} towards the south-east so we can represent it graphically, as shown below.

Let us consider positive j as north, negative j as south, positive i as east and negative i as west.
In vector form, we can write the velocity of the bird S as:
Vs=5j^{V_s} = - 5\hat j
The velocity of bird T in vector form can be expressed as:
VT=52sinθi^+52cosθj^{V_T} = 5\sqrt 2 \sin \theta \hat i + 5\sqrt 2 \cos \theta \hat j
The direction of bird T is south-west, so we can substitute 4545^\circ for θ\theta in the above expression.
VT=52sin45i^+52cos45j^{V_T} = 5\sqrt 2 \sin 45^\circ \hat i + 5\sqrt 2 \cos 45^\circ \hat j
Taking direction into consideration, we can write:
VT=5i^5j^{V_T} = - 5\hat i - 5\hat j
Let us write the expression for the relative velocity of bird S with respect to bird T.
VST=VSVT{V_{ST}} = {V_S} - {V_T}
On substituting 5j^ - 5\hat j for VS{V_S} and 5i^5j^ - 5\hat i - 5\hat j for VT{V_T} in the above expression, we get:

{V_{ST}} = - 5\hat j - \left( { - 5\hat i - 5\hat j} \right)\\\ = 5\hat i \end{array}$$ We know that the positive i represents the east direction. Therefore, bird S's relation velocity with respect to bird T is $$5{\rm{ }}{{\rm{m}} {\left/ {\vphantom {{\rm{m}} {\rm{s}}}} \right. } {\rm{s}}}$$ east, and option (B) is correct. **Note:** Do not forget to consider the sign conventions while writing the velocity in vector form. Although we can decide the positive or negative direction as per our convenience, it is better to consider the downward direction as negative and upward as positive.