Question
Question: Bird S is flying at \[5{\rm{ }}{{\rm{m}} {\left/ {\vphantom {{\rm{m}} {\rm{s}}}} \right. } {\r...
Bird S is flying at 5m/mss towards south, and bird T is flying at 52m/mss towards the south-east. Then, velocity of bird S relative to bird T is:
A. 102m/mss South-West
B. 5m/mss West
C. 102m/mss North-West
D. 5m/mss East
Solution
The relative velocity of bird S relative to bird T is equal to the difference of their absolute velocities. We will draw the directions of bird S and bird T graphically, and we will find that the bird S is moving at an angle of 45∘ with east and south.
Complete step by step answer:
Let us first draw all the possible directions.
Here S represents the south, W represents the west, E represents east, and N represents north direction.
It is given that bird S is flying with 5m/mss towards the south, and bird T is flying with 52m/mss towards the south-east so we can represent it graphically, as shown below.
Let us consider positive j as north, negative j as south, positive i as east and negative i as west.
In vector form, we can write the velocity of the bird S as:
Vs=−5j^
The velocity of bird T in vector form can be expressed as:
VT=52sinθi^+52cosθj^
The direction of bird T is south-west, so we can substitute 45∘ for θ in the above expression.
VT=52sin45∘i^+52cos45∘j^
Taking direction into consideration, we can write:
VT=−5i^−5j^
Let us write the expression for the relative velocity of bird S with respect to bird T.
VST=VS−VT
On substituting −5j^ for VS and −5i^−5j^ for VT in the above expression, we get: