Solveeit Logo

Question

Question: Binding energy per nucleon of <sub>1</sub>H<sup>2</sup> and <sub>2</sub>He<sup>4</sup> are 1.1. MeV ...

Binding energy per nucleon of 1H2 and 2He4 are 1.1. MeV and 7.0 MeV respectively. Energy released in the process 1H2 + 1H2 =2He4 is –

A

20.8 MeV

B

16.6 MeV

C

25.2 MeV

D

23.6 MeV

Answer

23.6 MeV

Explanation

Solution

Energy released DE = Total binding energy of 2He4 – 2(total binding energy of 1H2)

= 4 × 7.0 – 2(1.1) (2)

= 23.6 MeV