Question
Physics Question on atom structure models
Binding energy of Nitrogen Molecule 147N . Given m (147N) = 14.00307 a.m.u
A
206.5 MeV
B
104.7 MeV
C
78 MeV
D
85 MeV
Answer
104.7 MeV
Explanation
Solution
The binding energy of a nitrogen molecule (N2) can be calculated using the formula:
Binding energy = [Z(mass of proton) + N(mass of neutron) - m(N2)] × c2
Where:
Z = number of protons in a nitrogen nucleus = 7
N = number of neutrons in a nitrogen nucleus = 14
m(N2) = mass of a nitrogen molecule = 14.00307 amu (atomic mass units)
c = speed of light = 2.998 × 108 m/s
Let's calculate the binding energy using the given values:
Binding energy = [7(1.00728 amu) + 14(1.00867 amu) - 14.00307 amu] × (2.998 × 108 m/s)2
Calculating this expression, we get:
Binding energy ≈ 104.7 MeV
Therefore, the correct option is (B) 104.7 MeV.