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Question

Chemistry Question on p -Block Elements

BF3BF_3 on hydrolysis gives

A

\ceH3BO3+HF\ce{H_3BO_3 + HF}

B

\ceH3BO3+HBF4\ce{H_3BO_3 + HBF_4}

C

\ceB(OH)3+B2O3\ce{B (OH)_3 + B_2O_3}

D

\ceH3BO3+F2\ce{H_3BO_3 + F_2}

Answer

\ceH3BO3+HBF4\ce{H_3BO_3 + HBF_4}

Explanation

Solution

4 BF3+3 H2O−>H3BO3+3 HBF4. {4 \, BF_3 + 3 \, H_2O -> H_3BO_3 + 3 \, HBF_4.}