Question

Between the plates of parallel plate capacitor of capacity C, two parallel plates of the same material and area same as the plate of the original capacitor, are placed. If the thickness of these plates is equal to 1/5th of the distance between the plates of the origin

• A. $\frac{5}{3}C$
• B. $\frac{3}{5}C$
• C. $\frac{3C}{10}C$
• D. $\frac{10C}{3}C$

Answer 1

Answer: (A)

$\frac{5}{3}C$

Answer 2

Thickness of each plates $= \frac{1}{5}$ distance between plates
\hspace40mm = \frac{1}{5} \times d
The capacitance of capacitor is given by
\hspace40mm C_1 = \frac{\varepsilon_0 A}{d-t} \hspace40mm ... (i)
Thickness of two conductor is given by
\hspace40mm t = 2 \big(\frac{d}{5}\big) = \frac{2d}{5}
Putting the values oft in E (i)
\hspace40mm C_1 = \frac{\varepsilon_0 A}{d - \frac{2d}{5}} = \frac{5}{3} \frac{\varepsilon_0 A}{d}
\hspace40mm = \frac{5}{3}C \hspace30mm \big(where \, C = \frac{\varepsilon_0 A}{d}