Question
Question: Benzene diazonium chloride when treated with dilute H<sub>2</sub>SO<sub>4</sub> and strongly heated ...
Benzene diazonium chloride when treated with dilute H2SO4 and strongly heated gives
A
Benzene sulphonic acid
B
Benzene sulphonyl chloride
C
Benzene
D
Phenol
Answer
Benzene
Explanation
Solution
Friedel Craft’s reaction involves the formation of carbonium ion. When n-propyl chloride is used then the n-propyl carbonium ion converts to statble isopropyl carbonium ion and cumene. (Isopropyl benzene) is the product.