Question

Benzene diazonium chloride on reaction with phenol in weakly basic medium gives:
A.Diphenyl ether
B.P-hydroxy azobenzene
C.Chlorobenzene
D.Benzene

Answer 1

In the given question it is asked about the product that would form at the reaction of Benzene diazonium chloride and phenol. Now as the medium is basic then it indicates that the product that will form would be of the nature of ortho-substituted and acid reduced which gives us the right option and the final product as the P-hydroxy azobenzene.

Complete step by step solution:
In the given question we have to find out the product we would going to obtain when the reaction of the mentioned Benzene diazonium chloride having a chemical formula of ${C_6}{H_5} - N \equiv {N^ + }C{l^ - }$ will going to react with the other mentioned compound of phenol having the chemical formula of ${C_6}{H_5} - OH$
Now in the analysis, we get some of the facts that govern the formation of the product. They are:
First of all the coming of the basic medium would make it a kind of neutralization reaction as the formation of acid would take place to further carry the neutralization.
Apart from that, we get that the presence of the $-OH$ will make it as an ortho, para directing nature.
Now the reaction will take place to generate the mole of acid which is here $HCl$.
After conducting all this data we can clearly say that the reaction will take place as such:
${C_6}{H_5} - N \equiv {N^ + }C{l^ - } + {C_6}{H_5} - OH \to {C_6}{H_5} - N \equiv N - {C_6}{H_4} - OH$
Now in this reaction, the obtained molecule of the product is the p-hydroxy azobenzene.
So that gives us that the correct option would be option P-hydroxy azobenzene.

Hence, the correct answer is option B.

Note: Benzenediazonium chloride is an organic compound. It is a salt of a diazonium cation and chloride. It exists as a colourless solid that is soluble in polar solvents including water. It is the parent member of the aryl diazonium compounds, which are widely used in organic chemistry.