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Question: Bell metal contains \(80\,\% \) copper. The mass of Bell metal which contains \(1.5 \times {10^{20}}...

Bell metal contains 80%80\,\% copper. The mass of Bell metal which contains 1.5×10201.5 \times {10^{20}} atoms of copper is (Cu=64)\left( {Cu = 64} \right).
(A) 2mg2\,\,mg.
(B) 20mg20\,\,mg.
(C) 40mg40\,\,mg.

Explanation

Solution

Avogadro's constant is a number of units in one mole of any of the substance that is it is explained as its molecular weight in grams, which is equal to 6.022×10236.022 \times {10^{23}}. The units may be electrons, atoms, ions, or molecules, which depends on the nature of the substance and the character of the reaction.

Formula used:
Mass of the bell metal is found by;
m=M×Mmm = M \times {M_m}
Where, mm denotes the mass of the bell metal, MM denotes the number of moles present in the bell metal, Mm{M_m} denotes the molar mass of the bell metal.

Complete step by step answer:
The data given in the problem are as follows;
Number of atoms of copper is 1.5×10201.5 \times {10^{20}}.
Molar mass of the copper is, 64gmol164\,\,g\,mo{l^{ - 1}}.
Percentage of copper present in bell metal is, 80%80\,\% .

To find the number of moles in the bell;
According to Avogadro’s constant, we know that 11 mole of any substance has exactly 6.022×10236.022 \times {10^{23}} atoms or molecules in it;
That is;
6.022×10236.022 \times {10^{23}} atoms =1mole = 1\,\,mole
Then for 1.5×10201.5 \times {10^{20}} of atoms;
M=1×1.5×10206.022×1023     M=0.00025mol  M = 1 \times \dfrac{{1.5 \times {{10}^{20}}}}{{6.022 \times {{10}^{23}}}} \\\ \implies M = 0.00025\,\,mol \\\

Mass of the bell metal is found by;
m=M×Mmm = M \times {M_m}
Substitute the values of number of moles in the bell metal and the molar mass of the copper bell metal in the above equation;
m=0.00025mol×64gmol1     m=0.00025×64     m=0.016g  m = 0.00025\,\,mol \times 64\,\,g\,mo{l^{ - 1}} \\\ \implies m = 0.00025 \times 64 \\\ \implies m = 0.016\,\,g \\\

By calculating the percentage of the copper with the total weight percentage;
m=80100×0.016     m=0.02g  m = \dfrac{{80}}{{100}} \times 0.016 \\\ \implies m = 0.02\,\,g \\\
Converting the found mass from gram into milligram;
m=20mgm = 20\,\,mg

Therefore, the piece of metal of the bell consists of m=20mgm = 20\,\,mg.

So, the correct answer is “Option B”.

Note:
The molar mass of any of the chemical compounds is detailed as the mass of a sample of that compound which is divided by the amount of substance in that particular sample, which is measured in moles.
The molar mass is a volume and not a molecular property of a substance.