Question
Mathematics Question on mathematical reasoning
(p∧r)⇔(p∧(∼q))is equivalent to (~ p) when r is
A
p
B
∼p
C
q
D
∼q
Answer
q
Explanation
Solution
The truth table
Clearly p∧q⇔p∧∼q≡∼p
∴r=q
(p∧r)⇔(p∧(∼q))is equivalent to (~ p) when r is
p
∼p
q
∼q
q
The truth table
Clearly p∧q⇔p∧∼q≡∼p
∴r=q