Question
Question: \[\begin{aligned} & A\xrightarrow{4KOH,{{O}_{2}}}\underset{green}{\mathop{2B}}\,+2{{H}_{2}}O \\\...
& A\xrightarrow{4KOH,{{O}_{2}}}\underset{green}{\mathop{2B}}\,+2{{H}_{2}}O \\\
& 3B\xrightarrow{4HCL}\underset{purple}{\mathop{2C}}\,+Mn{{O}_{2}}+2{{H}_{2}}O \\\
& 2B\xrightarrow{{{H}_{2}}O,KI}2A+2KOH+D \\\
\end{aligned}$$
In the above sequence of reactions, A and D respectively are:
(A) $KI{{O}_{3}}and\text{ Mn}{{\text{O}}_{3}}$
(B) $KIand\text{ }{{\text{K}}_{2}}\text{Mn}{{\text{O}}_{4}}$
(C) $Mn{{O}_{2}}\text{and KI}{{\text{O}}_{3}}\text{ }$
(D) $KIand\text{ KMn}{{\text{O}}_{4}}$
Explanation
Solution
To solve this type of question it is important to know about the reagents used like in the first reaction the reagent is KOH, so we should know that KOH is hygroscopic and it is a water soluble base and oxygen means that after reaction with potassium hydroxide oxidation will takes place.
Complete step by step solution:
Reactions given in the question is mentioned below: