Question

Beena got married 8 years ago. Today, her age is $\frac {11}{4}$ times her age at the time of marriage. If her daughter‘s age is $\frac {1}{10}$ times her age, then her daughter‘s age is:

• A. 3 years
• B. 4 years
• C. 5 years
• D. 2 years

Answer 1

Answer: (B)

4 years

Answer 2

The correct option is (B): 4 years .